Multiple choice

In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option. $I. (2x^{2} – 7x + 3 = 0)$ $II. (2y^{2} – 7y + 6 = 0)$

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or relationship between x and y cannot be determined
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Equation I: 2x² - 7x + 3 = 0 factors as (2x-1)(x-3)=0, so x = 1/2 or x = 3. Equation II: 2y² - 7y + 6 = 0 factors as (2y-3)(y-2)=0, so y = 3/2 or y = 2. Comparing values: x values are 0.5 and 3, y values are 1.5 and 2. When x=0.5, xy for y=1.5 and x>y for y=2. Since we can have x>y or x

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