Multiple choice

In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option.\newline I. (4x^2 - 17x + 18 = 0)\newline II. (2y^2 - 21y + 40 = 0)

  1. If x > y

  2. If x ≤ y

  3. If x ≥ y

  4. If x < y

  5. If x = y or the relationship cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solve equation I: 4x² - 17x + 18 = 0 factors to (4x-9)(x-2) = 0, so x = 9/4 = 2.25 or x = 2. Solve equation II: 2y² - 21y + 40 = 0 factors to (2y-5)(y-8) = 0, so y = 5/2 = 2.5 or y = 8. Comparing values: x can be 2 or 2.25, while y can be 2.5 or 8. When x = 2 or 2.25, both values are less than both y values (2.5 and 8). Therefore x < y always.

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