In the questions given below you have to find the value of x and y and then compare the value of x and y and give the answer related to this.\newline I. (3x^2 + 2x - 21 = 0), \newline II. (3y^2 - 19y + 28 = 0)

For equation I: 3x² + 2x - 21 = 0 factors to (3x-7)(x+3) = 0, giving x = 7/3 or x = -3. For equation II: 3y² - 19y + 28 = 0 factors to (3y-7)(y-4) = 0, giving y = 7/3 or y = 4. Comparing values: when x = -3, x is less than both y values; when x = 7/3, x equals y in one case and is less than y = 4 in the other. In all cases, x ≤ y, so option D is correct.