Multiple choice

In the questions given below you have to find the value of x and y and then compare the value of x and y and give the answer related to this.\newline I. (4x^2 + 19x + 21 = 0), \newline II. (3y^2 – 19y – 14 = 0)

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \ge y\)$
  4. $\(x \le y\)$

  5. x = y, or relation can’t be established
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For equation I: 4x² + 19x + 21 = 0 factors to (4x+7)(x+3) = 0, giving x = -7/4 or x = -3. For equation II: 3y² - 19y - 14 = 0 factors to (3y+2)(y-7) = 0, giving y = -2/3 or y = 7. Comparing values: when x = -3, x < y for both y values; when x = -7/4, x < y for both y values. Since x is always less than y, option B (x < y) is correct.

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