Multiple choice

Find the values of (x) and (y) and compare them. I. (4x^2 + 3x - 27 = 0) II. (3y^2 - 20y + 32 = 0)

  1. x > y

  2. x < y

  3. x ≥ y

  4. x ≤ y

  5. x = y, or relation can’t be established
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Equation I: 4x² + 3x - 27 = 0. Roots are x = 9/4 and x = -3. Equation II: 3y² - 20y + 32 = 0. Roots are y = 4/3 and y = 8. Comparing all values of x with all values of y: 9/4 = 2.25 < 4/3 ≈ 4.33 and < 8; -3 < 4/3 and -3 < 8. Therefore x < y for all cases.

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