Multiple choice

In the following question two equations numbered I and II are given. You have to solve both the equations and give answer. $I. (2x^2 + 9x + 7 = 0)$ $II. (2y^2 + 9y + 10 = 0)$

  1. x > y

  2. x < y

  3. x ≥ y

  4. x ≤ y

  5. x = y or relation cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation I: 2x²+9x+7=0 factors as (2x+7)(x+1)=0, so x=-7/2 or x=-1. Solving equation II: 2y²+9y+10=0 factors as (2y+5)(y+2)=0, so y=-5/2 or y=-2. Comparing values: x=-3.5 or -1, y=-2.5 or -2. When x=-3.5 and y=-2, xy. When x=-1 and y=-2.5, x>y. Since x can be greater or less than y depending on which roots we choose, no definite relation can be established.

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