Multiple choice

In the following question two equations numbered I and II are given. You have to solve both the equations and give answer. $(I. 30x^2 + 11x + 1 = 0 )$ $(II. 42y^2 + 13y + 1 = 0)$

  1. x > y

  2. x < y

  3. x ≥ y

  4. x ≤ y

  5. x = y or relation cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solving equation I: 30x²+11x+1=0 factors as (5x+1)(6x+1)=0, so x=-1/5 or x=-1/6. Solving equation II: 42y²+13y+1=0 factors as (6y+1)(7y+1)=0, so y=-1/6 or y=-1/7. Comparing values: x values are -0.2 or -0.1667, y values are -0.1667 or -0.1429. The common value is -1/6=-0.1667. For x=-1/5=-0.2 and y=-1/7=-0.1429, we have x

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