Multiple choice

In the following question two equations numbered I and II are given. You have to solve both the equations and give answer thereof. $I. (3x^2 + 23x + 44 = 0) II. (3y^2 + 20y + 33 = 0)$

  1. x > y

  2. x ≥ y

  3. x < y

  4. x ≤ y

  5. x = y, or relation cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Equation I: 3x²+23x+44 = (3x+11)(x+4) = 0, so x = -11/3, -4. Equation II: 3y²+20y+33 = (3y+11)(y+3) = 0, so y = -11/3, -3. Compare: x = -3.67 and y = -3.67 (equal), or x = -4 and y = -3 (x < y). In all cases x ≤ y. Option D correct.

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