Multiple choice

Find the values of variables and state the correct relationship- (x^2 - 3x + 2 = 0) (2y^2 + 3y - 2 = 0)

  1. $\(x < y\)$
  2. $\(x > y\)$
  3. $\(x \le y\)$
  4. $\(x \ge y\)$

  5. x = y or Relation cannot be established
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving x² - 3x + 2 = 0 gives x = 1 or x = 2. Solving 2y² + 3y - 2 = 0 gives y = 0.5 or y = -2. When x = 1: x > y for both y values. When x = 2: x > y for both y values. Thus x > y always.

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