Multiple choice

Find the values of variables and state the correct relationship- (x^2 - 2x - 35 = 0) (y^2 - 12y + 32 = 0)

  1. $\(x < y\)$
  2. $\(x > y\)$
  3. $\(x \le y\)$
  4. $\(x \ge y\)$

  5. x = y or Relation cannot be established
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E Correct answer
Explanation

Solving x² - 2x - 35 = 0 gives x = 7 or x = -5. Solving y² - 12y + 32 = 0 gives y = 8 or y = 4. When x = 7: x < y for y=8 but x > y for y=4. When x = -5: x < y for both. The relationship cannot be established uniquely.

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