Multiple choice

Find the values of variables and state the correct relationship-(x^2+10x+21=0)(y^2-2y-8=0)

  1. $\(x < y\)$
  2. $\(x > y\)$
  3. $\(x \le y\)$
  4. $\(x \ge y\)$

  5. x = y or Relation cannot be established
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A Correct answer
Explanation

Solving x² + 10x + 21 = 0 gives x = -3 or x = -7. Solving y² - 2y - 8 = 0 gives y = -2 or y = 4. Since both x values (-3, -7) are less than both y values (-2, 4), x < y is always true.

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