Two equations (I) and (II) are given in each question. On the basis of these equations you have to decide the relation between ‘x’ and ‘y’ and give answer.(I: 12x^2 + x - 13 = 0 )(II: 6y^2 + 11y + 3 = 0)

Solving 12x² + x - 13 = 0 gives x = 1 or x = -13/12. Solving 6y² + 11y + 3 = 0 gives y = -0.5 or y = -1. When x = 1, x > y for both y values. When x = -13/12 ≈ -1.083, we have: compared to y = -0.5, x < y; compared to y = -1, x < y. Since x can be greater or less than y depending on the values chosen, the relationship cannot be established.