In the following questions, two equations (x) and (y) are given. You have to solve both the equations and give answer. (I.) (x^{3} - 133 = [56\% \text{ of } 1250] \div 4 + 1331 + 124\times9 \div 2) (II.) (y^{2} - y - 72 = 0)

Equation I: x³ - 133 = [56% of 1250] ÷ 4 + 1331 + 124×9 ÷ 2. 56% of 1250 = 700. 124×9÷2 = 558. So x³ - 133 = 700÷4 + 1331 + 558 = 175 + 1331 + 558 = 2064. x³ = 2064 + 133 = 2197. x = ∛2197 = 13. Equation II: y² - y - 72 = 0. Factoring: (y-9)(y+8) = 0, so y = 9 or y = -8. Since x = 13, and 13 > 9 (and 13 > -8), we have x > y for both solutions of y.