In the following questions, two equations Quantity I and Quantity II are given. You have to solve both the equations and give answer. \text{Quantity I:} x^3 - 133 = [56\% \text{ of } 1250] \div 4 + 11^3 + 124\times9 \div 2 \text{Quantity II:} y^2 - y - 72 = 0

Quantity I: x^3 - 133 = [56% of 1250] ÷ 4 + 11^3 + 124 × 9 ÷ 2. Calculate: 56% of 1250 = 0.56 × 1250 = 700. Then: 700 ÷ 4 = 175; 11^3 = 1331; 124 × 9 = 1116; 1116 ÷ 2 = 558. Sum: 175 + 1331 + 558 = 2064. So x^3 - 133 = 2064, thus x^3 = 2197, and x = 13. Quantity II: y^2 - y - 72 = 0 factors to (y - 9)(y + 8) = 0, so y = 9 or y = -8. Comparing x = 13 with y values: 13^3 = 2197, while 9^2 = 81 and (-8)^2 = 64. Since 2197 > 81 and 2197 > 64, Quantity I > Quantity II.