Multiple choice

Find the value of variables and state the correct relationship-\ If (24x^2 - 122x + 10 = 0) and (2y^2 + 5y + 3 = 0) then

  1. $x < y$
  2. $x > y$
  3. $x \le y$
  4. $x \ge y$
  5. $x = y or Relation cannot be established$
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B Correct answer
Explanation

For 24x² - 122x + 10 = 0: using quadratic formula, x = (122 ± √14884 - 960)/48 = (122 ± √13924)/48. √13924 ≈ 118, so x ≈ (122 + 118)/48 ≈ 5 or x ≈ (122 - 118)/48 ≈ 0.08. For 2y² + 5y + 3 = 0: discriminant = 25 - 24 = 1, so y = (-5 ± 1)/4, giving y = -1 or y = -1.5. Since all x values (0.08, 5) are greater than all y values (-1.5, -1), we have x > y.

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