Multiple choice

Find the value of variables and state the correct relationship- If (12x^2 + 37x + 21 = 0) and (6y^2 - 32y + 42 = 0) then

  1. x < y

  2. x > y

  3. x ≤ y

  4. x ≥ y

  5. x = y or Relation cannot be established
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A Correct answer
Explanation

For 12x² + 37x + 21 = 0: factors as (3x+7)(4x+3) = 0, giving x = -7/3 ≈ -2.33 or x = -3/4 = -0.75. For 6y² - 32y + 42 = 0: dividing by 2 gives 3y² - 16y + 21 = 0, which factors as (y-3)(3y-7) = 0, so y = 3 or y = 7/3 ≈ 2.33. All x values (-2.33, -0.75) are less than all y values (2.33, 3), so x < y.

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