Multiple choice

Find the value of variables and state the correct relationship-\If (2x^2 + 10x - 28 = 0) and (4y^2 - 19y + 21 = 0) then

  1. $x < y$
  2. $x > y$
  3. $x \le y$
  4. $x \ge y$

  5. x = y or Relation cannot be established
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E Correct answer
Explanation

For 2x² + 10x - 28 = 0: dividing by 2 gives x² + 5x - 14 = 0, which factors as (x+7)(x-2) = 0, so x = -7 or 2. For 4y² - 19y + 21 = 0: using quadratic formula gives y = (19 ± √361-336)/8 = (19 ± 5)/8, so y = 3 or 1.75. Comparing: x can be -7 or 2, y can be 1.75 or 3. The values overlap (2 < 3 but 2 > 1.75), so no clear relationship exists.

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