In each of the following questions two equations (I) and (II) are given. Solve these equations and give the answer:\ (I) (x^2 - 11\sqrt{3}x + 84 = 0)\ (II) (y^2 - 16\sqrt{3}x + 84 = 0)

For equation (I), using the quadratic formula: x = [11√3 ± √((11√3)^2 - 4×84)]/2 = [11√3 ± √(363 - 336)]/2 = [11√3 ± √27]/2 = [11√3 ± 3√3]/2, giving x = 7√3 or x = 4√3. For equation (II), the variable should be y, not x (this is a typo in the question). Solving y^2 - 16√3y + 84 = 0 gives y = [16√3 ± √768]/2 = [16√3 ± 8√3]/2, giving y = 14√3 or y = 6√3. Numerically: x ≈ 12.12 or 6.93, y ≈ 24.25 or 10.39. Depending on the pair chosen, x can be less than or greater than y, so no relationship can be established.