Multiple choice

In the following question two equation numbered I and II are given you have to solve both the equations and give answer. $I. (2x^2 + 11x + 14 = 0) II. (4y^2 + 12y + 9 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x=y or the relationship cannot be established.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation I: 2x^2 + 11x + 14 = 0 gives x = -2 or x = -3.5. Solving equation II: 4y^2 + 12y + 9 = 0 gives y = -1.5 only. When x = -2, we have x < y (-2 < -1.5). When x = -3.5, we also have x < y (-3.5 < -1.5). Therefore, x is always less than y.

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