Multiple choice

Find the value of variables and state the correct relationship.\newline I. (x^2 - 1 = 0)\newline II. (y^2 + 4y + 3 = 0)

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \ge y\)$
  4. $\(x \le y\)$

  5. x = y or relation cannot be established
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C Correct answer
Explanation

Solving equation I: x^2 - 1 = 0 gives x^2 = 1, so x = 1 or x = -1. Solving equation II: y^2 + 4y + 3 = 0. Factoring: (y + 3)(y + 1) = 0, so y = -3 or y = -1. Comparing all values: when x = 1, x > y for both y values; when x = -1, x > y when y = -3, but x = y when y = -1. Therefore, x is always greater than or equal to y.

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