Multiple choice

Find the value of variables and state the correct relation.(1.5 x^{2} + 8x - 49.5 = 0)(4.5 y^{2} - 2.8y + 0.4 = 0)

  1. $x > y$
  2. $x \ge y$
  3. $x < y$
  4. $x \le y$

  5. x = y or relationship cannot be stablished.
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For x: 1.5x² + 8x - 49.5 = 0. Using quadratic formula: x = [-8 ± √(64 + 297)]/3 = [-8 ± √361]/3 = [-8 ± 19]/3. So x = 11/3 ≈ 3.67 or x = -27/3 = -9. For y: 4.5y² - 2.8y + 0.4 = 0 → y = [2.8 ± √(7.84 - 7.2)]/9 = [2.8 ± √0.64]/9 = [2.8 ± 0.8]/9. So y = 3.6/9 = 0.4 or y = 2/9 ≈ 0.22. Since x can be 3.67 or -9 and y can be 0.4 or 0.22, we cannot establish a unique relationship - option E is correct.

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