Multiple choice

$I. (20x^2 - x - 12 = 0)$ $II. (20y^2 + 27y + 9 = 0)$ Solve the given equations and determine the relationship between x and y.

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For I: 20x²-x-12=0, using quadratic formula: x=(1±√(1+960))/40=(1±31)/40, so x=0.8 or x=-0.75. For II: 20y²+27y+9=0, y=(-27±√(729-720))/40=(-27±3)/40, so y=-0.6 or y=-0.75. Comparing: x=0.8 > y=-0.6, x=-0.75 = y=-0.75, x=-0.75 < y=-0.6. The relationship varies between values, so it cannot be established.

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