Multiple choice

In the following questions two equations (I) and (II) are given. You have to solve both the equations and give answer. ( (I) \space 5x^2 + 8x + 3 = 0 \space \space \space \space \space \space \space \space \space \space \space \space \space \space \space (II) \space 16y^2 - 40y + 25 = 0 )

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation (I): 5x² + 8x + 3 = 0 gives x = -0.6 or x = -1. Solving equation (II): 16y² - 40y + 25 = 0 factors as (4y-5)² = 0, giving y = 1.25 (repeated root). Both x values are less than y, so x < y.