Multiple choice

In each of the following questions, two equations (\textbf{(I)}) and (\textbf{(II)}) are given. You have to solve them and Give answer:(\textbf{(I)}) (2x^2 - 11x + 15 = 0)(\textbf{(II)}) (2y^2 - 15y + 28 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve (I): 2x²-11x+15=0 factors to (2x-5)(x-3)=0, so x=2.5 or x=3. Solve (II): 2y²-15y+28=0 factors to (2y-7)(y-4)=0, so y=3.5 or y=4. All x values (2.5, 3) are less than all y values (3.5, 4), so x

Keep practicing — related questions