In the following questions two equations I and II are given. You have to solve both the equations and give answer. $(\text{(I)}\quad x^2 – 3x – 460 = 0 \qquad \text{(II)}\quad y^2 – 5y – 500 = 0)$

Equation I: x² - 3x - 460 = 0. Using quadratic formula or factorization: x = [3 ± √(9+1840)]/2 = [3 ± √1849]/2 = [3 ± 43]/2. So x = 23 or x = -20. Equation II: y² - 5y - 500 = 0. y = [5 ± √(25+2000)]/2 = [5 ± √2025]/2 = [5 ± 45]/2. So y = 25 or y = -20. Comparing: when x = 23 and y = 25: x < y. When x = 23 and y = -20: x > y. Since both x > y and x < y are possible, the relationship cannot be uniquely determined.