In the following questions two equations I and II are given. You have to solve both the equations and give answer. ( (I) ) ( 2x^2 + 14x – 120 = 0 ) ( (II) ) ( y^2 + 48y – 324 = 0 )

Equation I: 2x²+14x-120=0 divides by 2: x²+7x-60=0, factors as (x+12)(x-5)=0, so x = -12 or x = 5. Equation II: y²+48y-324=0. Complete square: (y+24)² = 324+576 = 900, so y+24 = ±30, giving y = 6 or y = -54. When x=-12: x > -54 but x < 6. When x=5: x < 6 but x > -54. Relationship depends on which root we pick. Option E is correct as no consistent relationship exists. Option D (x ≤ y) is incorrect because x=-12 > -54.