Multiple choice

In the following questions two equations numbered (I) and (II) are given. You have to solve the both equations and give answer— $( (I) \space 18x^2 + 18x + 4 = 0 \space \space \space \space \space (II) \space 12y^2 + 29y + 14 = 0 )$

  1. x<y

  2. x>y

  3. x≤y

  4. x≥y

  5. x=y or relation cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solving equation (I): 18x² + 18x + 4 = 0 gives x = -1/3 or x = -2/3. Solving equation (II): 12y² + 29y + 14 = 0 gives y = 7/12 or y = -11/12. Both values of x are less than both values of y, so x ≥ y holds true.

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