Multiple choice

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer- I. (12x^2 - 2x - 4 = 0) II. (10y^2 + 2 = 9y)

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \ge y\)$
  4. $\(x \le y\)$

  5. x = y or Relation can not be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Equation I: 12x² - 2x - 4 = 0 → 6x² - x - 2 = 0. Solving: x = (1 ± √49)/12 = (1 ± 7)/12, so x = 2/3 or x = -1/2. Equation II: 10y² - 9y + 2 = 0. Solving: y = (9 ± √81 - 80)/20 = (9 ± 1)/20, so y = 1/2 or y = 2/5. Since x can be > y or < y depending on which root you pick, no unique relation exists.

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