$In each of the following questions, two equations (I) and (II) are given. You have to solve them and(I) \space x^2 - 7x = -12\(II) \space y^2 - 9y = -20$ Give answer

Solving equation (I): x² - 7x = -12 becomes x² - 7x + 12 = 0, which factors as (x-3)(x-4) = 0, giving x = 3 or x = 4. Solving equation (II): y² - 9y = -20 becomes y² - 9y + 20 = 0, which factors as (y-4)(y-5) = 0, giving y = 4 or y = 5. When x = 3, x < y (since y is 4 or 5). When x = 4, we have x = y for y = 4, but x < y for y = 5. The relationship cannot be established for all cases, but the minimum value of x is 3 and the minimum value of y is 4, so x ≤ y is generally true.