Multiple choice

In the following questions one or two equations (I) and (II) are given. On the basis of these you have to find out the relation between x & y. $( (I) \quad x^2 + 9x + 20 = 0 )$ $( (II) \quad y^2 + 13y + 42 = 0 )$

  1. If x = y

  2. If x > y

  3. If y > x

  4. If x ≥ y

  5. If y ≥ x
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving (I): x² + 9x + 20 = 0 gives (x+4)(x+5) = 0, so x = -4 or -5. Solving (II): y² + 13y + 42 = 0 gives (y+6)(y+7) = 0, so y = -6 or -7. Comparing: when x = -4, y = -6 or -7, so x > y. When x = -5, y = -6 or -7, so x > y. In all cases x > y.

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