Multiple choice

Work efficiency of pipe - I is two and a half - times the work efficiency of pipe - II. If pipe - I can fill three - fifth part of the tank in 18 hours then in how many hours pipe - II will fill the whole tank alone? पाइप - I की कार्यक्षमता पाइप - II की कार्यक्षमता की ढाई गुना है | यदि पाइप - I टंकी के तीन - पांचवे भाग को 18 घंटे में भर देता है तो कितने घंटों में पाइप - II अकेले इस पूरी टंकी को भर देगा ?

  1. 45 hours/घंटे

  2. 50 hours/घंटे

  3. 60 hours/घंटे

  4. 75 hours/घंटे
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Pipe I fills 3/5 of tank in 18 hours, so it fills the whole tank in 18 × 5/3 = 30 hours. Pipe I's efficiency is 2.5 times Pipe II's efficiency, so Pipe II takes 2.5 × 30 = 75 hours to fill the tank alone. Therefore, the answer is 75 hours.

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