Multiple choice

A pipe A can fill the tank in 18 hours and the same tank is filled by B in half of the time taken by A. If both the pipes are open, then how much part of the tank is filled by them in 1 hour?

  1. $\(\frac{1}{6}\)$
  2. $\(\frac{2}{5}\)$
  3. $\(\frac{1}{9}\)$
  4. $\(\frac{2}{7}\)$
  5. $\(\frac{1}{7}\)$
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A Correct answer
Explanation

Pipe A fills 1/18 of tank per hour. Pipe B fills in 9 hours (half of 18), so fills 1/9 per hour. Combined rate = 1/18 + 1/9 = 1/18 + 2/18 = 3/18 = 1/6 of tank per hour.

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