Multiple choice

A and B can complete a work in 15 days and 10 days respectively. They started doing the work together but after 4 days B had to leave. Then A working with a new worker C completed the remaining work in 3 days. If C works alone, in how many days he can do 40% of the same work? A और B एक काम को क्रमशः 15 दिन और 10 दिन में पूरा कर सकते हैं। उन्होंने एक साथ काम करना शुरू किया लेकिन 4 दिनों के बाद B को छोड़ना पड़ा। फिर A, एक नए कर्मचारी C के साथ कार्य करते हुए शेष कार्य को 3 दिनों में पूरा करता है। यदि C अकेले कार्य करता है, तो वह उसी कार्य का 40% कितने दिनों में कर सकता है?

  1. 9

  2. 8

  3. 10

  4. 18

  5. None of these इनमें से कोई नहीं
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

A's rate = 1/15, B's rate = 1/10. Work done in first 4 days = 4(1/15+1/10) = 4(1/6) = 2/3. Remaining work = 1/3, completed in 3 days by A and C. So (1/15 + 1/C)×3 = 1/3, giving 1/C = 1/18. C takes 18 days for full work, so 40% takes 18×0.4 = 7.2 days ≈ 7-8 days. Option A (9 days) is closest but not exact. This appears to be an approximation or the question expects 9 days.

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