In each of the following questions, read the given statement and compare the Quantity I and Quantity II on its basis. Speed of train A is 72 km/hr whose length is half of length of a platform & crosses the platform in 12 sec. Quantity I: 50% of sum of length of train A and length of platform. Quantity II: Length of train B which travel with 50% of speed of train A and crosses the train A in 10 sec when coming from opposite direction.

Speed of train A = 72 km/hr = 20 m/s. Let platform length = P, then train length = P/2. Total distance to cross platform = P + P/2 = 3P/2 = 20 * 12 = 240 m. So platform = 160 m, train = 80 m. Quantity I = 50% of (160 + 80) = 120 m. Train B speed = 50% of 72 = 36 km/hr = 10 m/s. Relative speed when opposite = 20 + 10 = 30 m/s. Time = 10 sec, so train B length = 30 * 10 - 80 = 220 m (distance = sum of both train lengths). Therefore Quantity I (120 m) < Quantity II (220 m).