Multiple choice

A Train started his journey from station P towards station Q. After 3 hours of his journey it meets with an accident due to that it resumes its journey after 2 h with 3/4th of its usual speed and reached his destination 5 hours late. If the accident was held 150 km far then it reached its destination 4.5 hours late. Find the distance between the stations. एक ट्रेन ने स्टेशन P से स्टेशन Q की ओर अपनी यात्रा शुरू की। अपनी यात्रा के 3 घंटे बाद यह एक दुर्घटनाग्रस्त हो जाती है, पुनः 2 घंटे के बाद अपनी यात्रा फिर से शुरू करती है अपनी सामान्य गति के 3 / 4th के साथ और 5 घंटे देरी से अपने गंतव्य पर पहुंचती है। यदि दुर्घटना 150 किमी दूर आयोजित की गई थी तो यह 4.5 घंटे देरी से अपने गंतव्य तक पहुंची। स्टेशनों के बीच की दूरी ज्ञात कीजिए।

  1. 1250

  2. 1460

  3. 1320

  4. 1200

  5. 1150
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let D be total distance and V be usual speed. Normal time = D/V. In first scenario: accident at 3V km, 2-hour stop, then (D-3V) distance at 3V/4 speed. Time taken = 3 + 2 + (D-3V)/(3V/4) = 5 + 4(D-3V)/3V = 5 + 4D/3V - 4 = 4D/3V + 1. Delay = 4D/3V + 1 - D/V = D/3V + 1 = 5, so D/V = 12. In second scenario: accident at (3V+150) km. Time = (3V+150)/V + 2 + (D-3V-150)/(3V/4) = 3 + 150/V + 2 + 4(D-3V-150)/3V = 5 + 150/V + 4D/3V - 4 - 200/V = 4D/3V + 1 - 50/V. Delay = 4D/3V + 1 - 50/V - D/V = D/3V + 1 - 50/V = 4.5. Substituting D/V = 12: 4 + 1 - 50/V = 4.5, so 50/V = 0.5, V = 100 km/h. Then D = 1200 km. This matches option D.

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