Multiple choice

Quantity I : The distance travelled by a bus in 4 hours is 320 km. If the speed of bus is increased by 20% then what will be the time taken by bus to cover the triple of distance? Quantity II: A bus which is travelling from point A to point B which are 150 km apart, covers half of distance with 25 km/h and rest of distance with 30 km/hr and take break of 30 minutes after travelling half of distance then what will be the total time taken by bus to reach destination?

  1. Quantity I > Quantity II

  2. Quantity I ≥Quantity II

  3. Quantity I < Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II or relation can’t be established
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A Correct answer
Explanation

Quantity I: Distance = 320 km, time = 4 hours, so original speed = 80 km/h. Increased by 20%: new speed = 96 km/h. Triple distance = 960 km. Time = 960 / 96 = 10 hours. Quantity II: First half (75 km) at 25 km/h takes 3 hours. Second half (75 km) at 30 km/h takes 2.5 hours. Break = 0.5 hours. Total time = 3 + 2.5 + 0.5 = 6 hours. Since 10 > 6, Quantity I > Quantity II.

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