In each of the following questions (quantity) two questions are given. Solve these questions and give answer: The average of the ages of A, B and C at present is 28 years. 7 years ago the ratio of ages of A and C was 1 : 4 and the age of B was 90% more than the age of C. I. After 8 years the age of C will be what percentage of the present age of A? II. After 8 years the age of A will be what percentage of the present age of B?

First find present ages: average 28 means A + B + C = 84. From 7 years ago: ratio A:C = 1:4 gives C = 4A - 21. B-7 = 1.9(C-7) so B = 1.9C - 6.3. Substituting C in terms of A and solving: A + (1.9(4A - 21) - 6.3) + (4A - 21) = 84 gives A = 25, C = 79, B = 143... wait that doesn't work. Let me redo: C = 4A - 21, B = 1.9(4A - 21) - 6.3 + 7 = 1.9(4A - 28) + 0.7 = 7.6A - 52.6. Then A + (7.6A - 52.6) + (4A - 21) = 84 means 12.6A = 157.6, A = 12.5, C = 29, B = 42.5. Quantity I: after 8 years C = 37, present A = 12.5, percentage = 37/12.5 × 100 = 296%. Quantity II: after 8 years A = 20.5, present B = 42.5, percentage = 20.5/42.5 × 100 = 48.2%. So Quantity I > Quantity II.