In the following question, two Quantity I and Quantity II are given. You have to solve both the Quantities and give answer. Quantity I: 5 year ago the of ages of Rita and Priya was 5 :2 , after 7 year the ratio of their age will be 3:2 , then find the age of Rita after 10 year ? Quantity II: today a father’s age is twice than his son’s age , after 6 year the ratio of their ages will become 23:13 then find the fathers age after 6 year ?

Quantity I: 5 years ago, Rita:Priya = 5:2, so (R-5):(P-5) = 5:2. After 7 years from now, (R+7):(P+7) = 3:2. From first equation: 2(R-5) = 5(P-5), 2R-10 = 5P-25, 2R = 5P-15. From second: 2(R+7) = 3(P+7), 2R+14 = 3P+21, 2R = 3P+7. Equating: 5P-15 = 3P+7, 2P = 22, P = 11. So 2R = 3(11)+7 = 40, R = 20. Rita after 10 years = 20+10 = 30. Quantity II: Father = 2×Son. After 6 years: (F+6):(S+6) = 23:13. F = 2S, so (2S+6):(S+6) = 23:13. 13(2S+6) = 23(S+6), 26S+78 = 23S+138, 3S = 60, S = 20. Father = 2×20 = 40. Father after 6 years = 46. Since 30 < 46, Quantity I < Quantity II.