Multiple choice

Find the correct relationship between given quantities. Quantity I: Present age of Zenith, if Age of Zenith is thrice of his son, 6 years ago he was four times of his son’s age. Quantity II: Present age of Zeshan, if ratio of himself's age and his wife's age was 17 : 15 at the time of marriage. Their son is 6 years old, who was born after two years of marriage. 2 years from now ratio age Zeshan’s wife and his son will be 5:1.

  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established

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A Correct answer
Explanation

For Quantity I: Let son's age 6 years ago be x. Then Zenith's age was 4x. Currently, son is (x+6) and Zenith is thrice that, so 4x+6 = 3(x+6). Solving gives x=12, so son is 18 and Zenith is 54. For Quantity II: Marriage was 6+2=8 years ago. At marriage, ages were 17k and 15k. Now wife is 15k+8, son is 6. In 2 years, wife will be 15k+10 and son will be 8. Given (15k+10)/8 = 5/1, solving gives k=2, so Zeshan is now 34+8=42. Comparing: 54 > 42, so Quantity I is greater.