Multiple choice

Quantity I- a grocer mix two varieties of pulses costing Rs. 15 and Rs. 20 per kg respectively so as to get a mixture worth Rs. 16.50 per kg. Find the sum of numerator and denominator of shortest term of the ratio in which these varieties are mixed. Quantity II- Find 150% of sum of numerator and denominator of shortest term of the ratio in which rice at Rs. 7.20 per kg must be mixed with rice at Rs. 5.70 per kg to produce a mixture worth Rs. 6.30 per kg.

  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established
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A Correct answer
Explanation

Quantity I: Using alligation, the ratio of Rs. 15 and Rs. 20 pulses to get Rs. 16.50 mixture is |16.50 - 15| : |16.50 - 20| = 1.50 : 3.50 = 3 : 7. Sum = 3 + 7 = 10. Quantity II: For Rs. 7.20 and Rs. 5.70 rice to get Rs. 6.30 mixture, the ratio is |6.30 - 5.70| : |6.30 - 7.20| = 0.60 : 0.90 = 2 : 3. Sum = 2 + 3 = 5. 150% of 5 = 7.5. Comparing: 10 > 7.5, so Quantity I > Quantity II.

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