Multiple choice

Given below are two quantities named I and II. Based on the given data, you have to determine the relation between them and mark the answer. \textbf{Quantity I-} in a 40 L mixture of milk and water , the water is only 10%, then find amount of water to be added to make the concentration 50%. \textbf{Quantity II-} in a 100 L mixture of petrol and spirit , the spirit is only 2%, then find the amount of spirit to be added to make spirit concentration 30%.

  1. Quantity I > Quantity II

  2. Quantity I < Quantity II

  3. Quantity I ≥ Quantity II

  4. Quantity I ≤ Quantity II

  5. Quantity I = Quantity II or relation can not be established
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Quantity I: In 40L with 10% water (4L water, 36L milk), let x be water added. New concentration = (4+x)/(40+x) = 0.5, so 4+x = 20+x/2, giving x = 32L. Quantity II: In 100L with 2% spirit (2L spirit, 98L petrol), let y be spirit added. (2+y)/(100+y) = 0.3, so 2+y = 30+0.3y, giving y = 40L. Thus Quantity I (32) < Quantity II (40).

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