Multiple choice

What is the percentage of chemical P in 90 litres of mixture C? Statement I: Mixture A having chemicals M, N and P in ratio 4:2:3 is mixed with mixture B having M, N and P in ratio 1:5:4, in 3:2 ratio to form mixture C. Statement II: From 75 litres of mixture C containing chemicals M, N and P, if N is separated by a chemical process and is added to 90 litres of mixture A having M, N and P ratio 4:2:3 then, the quantity of N in mixture A increases by 125%.

  1. Statement I is sufficient to answer the question.

  2. Statement II is sufficient to answer the question.

  3. Either Statement I or statement II is sufficient to answer the question.

  4. Neither Statement I nor statement II is sufficient to answer the question.

  5. Both Statements I and II are necessary to answer the question.
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Statement I: Mixture A (M:N:P = 4:2:3) mixed with Mixture B (M:N:P = 1:5:4) in 3:2 ratio. For 90L of mixture C: A contributes (3/5)×90 = 54L, B contributes (2/5)×90 = 36L. Chemical P in A: (3/9)×54 = 18L. Chemical P in B: (4/10)×36 = 14.4L. Total P in C = 18 + 14.4 = 32.4L. Percentage of P = (32.4/90) × 100 = 36%. Statement I alone is sufficient. Statement II involves separating N from mixture C and adding to mixture A, but this doesn't directly give us the percentage of P in mixture C without additional information.

Keep practicing — related questions