Multiple choice

A tent is of a shape of right circular cylinder up to a height of 4 meters and then becomes a right circular cone with maximum height of 52 meters above the base. If the radius of the base is 14 meters, then what is the cost of covering the inner side of the tent at the rate of Rs 4.5 per square meter? एक तम्बू 4 मीटर ऊपर तक बेलनाकार है और फिर एक शंकु बन जाता है यदि तम्बू की अधिकतम ऊचाई 52 मीटर है तथा आधार की त्रिज्या 14 मीटर है, तो तंबू के अंदरूनी हिस्से को 4.5 रुपये प्रति वर्ग मीटर की दर से ढकने के लिए लागत क्या आएगी?

  1. Rs. 11994 / 12884 रु.

  2. Rs. 15484 / 15484 रु

  3. Rs. 11484 / 11484 रु.

  4. Rs. 8484 / 8484 रु
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C Correct answer
Explanation

The tent consists of a cylinder (height 4m, radius 14m) and a cone (height 48m, radius 14m). Inner surface area = CSA of cylinder + CSA of cone = 2πrh + πrl = 2×(22/7)×14×4 + (22/7)×14×50 = 352 + 2200 = 2552 m². At Rs 4.5 per m², total cost = 2552 × 4.5 = Rs 11484. The slant height of cone l = √(48² + 14²) = 50m.

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