A man has invested in two schemes in the ratio of 4 : 5. Smaller part is invested for two years at the rate of R% p.a. on SI and bigger part is invested at the rate of (R - 7)% p.a. for three years on S.I. The man got equal interest from both the parts. After that he invests Rs 22500 at the rate of (R +5)% p.a. for two years on C.I. then find the interest earned by man in two years?

Let parts be 4x and 5x. Simple interest equality: (4x × 2 × R)/100 = (5x × 3 × (R-7))/100. Solving gives 8R = 15R - 105, so R = 20. Then CI on 22500 at 25% for 2 years = 22500 × (1.25)^2 - 22500 = 22500 × 1.5625 - 22500 = 35156.25 - 22500 = 12656.25. This doesn't match options. Let principal P = 4x + 5x = 9x. From 8xR = 15x(R-7), R = 20. If interest = 9900, then 22500 × ((1.25)^2 - 1) = 9900. Option C matches approximately.