Multiple choice

An alloy contains a mixture of two metals X and Y in the ratio of 2 : 3. The second alloy contains a mixture of the same metals, X and Y, in the ratio 7 : 3. In what ratio should the first and the second alloys be mixed so as to make a new alloy containing 50% of metal X?

  1. 3 : 4

  2. 3 : 1

  3. 5 : 6

  4. 2 : 1
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

First alloy has 2/5 metal X and 3/5 metal Y. Second alloy has 7/10 metal X and 3/10 metal Y. To achieve 50% metal X in the final mixture, we set up the equation: (ratio of first alloy) × (2/5) + (ratio of second alloy) × (7/10) = 1/2. Solving this gives the ratio 2:1 for first alloy to second alloy.

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