Two vessels A and B contain a mixture of milk and water. A mixture of 3 parts from A and 2 parts from B is found to contain 29% of milk and a mixture of 1 part from A and 9 parts from B is found to contain 34% of milk. Find the % of milk in B and A.

Let A have x% milk, B have y%. 3x + 2y = 87 and x + 9y = 102. Solving: 27x + 18y = 783 and 2x + 18y = 204. Subtracting: 25x = 579, x = 23.16. Wait, let me re-solve. From eq2: x = 102 - 9y. Substituting in eq1: 3(102 - 9y) + 2y = 87, giving 306 - 27y + 2y = 87, so -25y = -219, y = 8.76. Then x = 102 - 9(8.76) = 23.16. But option says 35&25. Let me verify: If A=25, B=35: 3(25)+2(35)=75+70=145 (not 87). My solution gives x=23.16, y=8.76. Neither matches option A. Let me check my equations: 3x + 2y should be 87 (29% of 3 parts from A and 2 parts from B means 0.29*5 = 1.45 total, so 3x+2y = 145). And 1x + 9y = 34% of 10 = 3.4, so x+9y = 340. Solving: from eq2, x = 340-9y. Substitute: 3(340-9y)+2y=145, 1020-27y+2y=145, -25y=-875, y=35. Then x=340-9(35)=340-315=25. So A=25%, B=35%. But option says 35&25, which means B=35 and A=25. The format is confusing.