A mixture contains 67.52 liters of water and remaining 60% of milk. If 20% of the mixture is replaced by water, then what would be the percentage of milk in the new mixture?

If the mixture is 60% milk, then water is 40%. Given 67.52 L water, total mixture = 67.52/0.4 = 168.8 L, so milk = 101.28 L. When 20% (33.76 L) is removed, it contains milk and water in the same ratio. Milk removed = 33.76 × 0.6 = 20.256 L, leaving 81.024 L milk. After adding pure water, total is unchanged at 168.8 L, so new milk % = (81.024/168.8) × 100 = 48%. The key is that removing a portion removes both components proportionally.