Multiple choice

Mixture of water and alcohol is 30 liters, in which water is 33.33% less than alcohol. Find the quantity of water added in the mixture so that water becomes 50% more than the alcohol.

  1. 24

  2. 15

  3. 12

  4. 20

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let alcohol = A. Water is 33.33% less = A - (1/3)A = 2A/3. Total = A + 2A/3 = 5A/3 = 30L, so A = 18L, water = 12L. Let x be water added. New water = 12 + x. We need water to be 50% more than alcohol: 12 + x = 1.5 × 18 = 27. Solving: x = 15L. Options A (24L) and D (20L) would make water exceed alcohol by much more than 50%.