The pattern is: nth term = n³ × (n+1), starting from n=2. Term 2: 2³ × 3 = 8 × 3 = 24, but we have 8. Let me recalculate. Actually it's: nth term = n³ × (n-1), starting from n=2. Term 2 (n=2): 8 × 1 = 8. Term 3 (n=3): 27 × 2 = 54, but we have 128. Another pattern: nth term = n³ × (position from end). Let me verify: 8 = 2³ × 1, 128 = 4³ × 2, 648 = 6³ × 3, so missing term (position 4) = 8³ × 4 = 512 × 4 = 2048. This matches option A. Continuing: 5000 = 10³ × 5 (1000 × 5), and 10368 = 12³ × 6 (1728 × 6). The series uses even numbers starting from 2: 2, 4, 6, 8, 10, 12.