Three containers A, B and C contain wine and water the ratio respectively 5:7, 7:9 and 4:5. Each container has equal volume of the mixture. If he took two-third of the quantity from container A, four – fifth quantity from container B and half quantity from container C and mixed in another container D. What is the ratio of wine to water in container D?

Let each container have V liters. Container A (wine:water = 5:7): taking 2/3 gives wine = 5/12 × 2V/3 = 10V/36, water = 7/12 × 2V/3 = 14V/36. Container B (7:9): taking 4/5 gives wine = 7/16 × 4V/5 = 28V/80, water = 9/16 × 4V/5 = 36V/80. Container C (4:5): taking 1/2 gives wine = 4/9 × V/2 = 4V/18, water = 5/9 × V/2 = 5V/18. Total wine = 612V/720, total water = 804V/720. Ratio = 612:804 = 51:67.